bartshan-83 Posted June 23, 2010 Posted June 23, 2010 I got one of those daily calendars on my desk and it has a puzzle, word game, trivia, etc. every day. I spend a few minutes on it each morning when I get in. Some are fun, some are stupid. As long as they aren't too dumb, I'll try to post the daily one each day. I'll start you off with a pretty easy one from today: A sealed rectangular box measuring 8x6x18 contains 864 sugar cubes, each measuring 1x1x1. How many of the sugar cubes are touching the box?
SonOfWade Posted June 23, 2010 Posted June 23, 2010 269? Edit: That's wrong. Gotta be 864-(6*4*16)=480
CountDorkula Posted June 23, 2010 Posted June 23, 2010 269? Edit: That's wrong. Gotta be 864-(6*4*16)=480 Trying to figure this out. Did you take into account that the corner pieces are touching the wall 2x's and would only count as one. The number just does not seem right to me. I did the same math. It seems a little high. I got 269 for my first guess then 384 not sure how i got that number. . .
BillsFanInTexas Posted June 23, 2010 Posted June 23, 2010 592? Sides 1&3 = 18x8 = 144x2 = 288 Sides 2&4 = 16x8 = 128x2 = 256 Short sides = 4x6 = 24x2 = 48 sum = 592 Seems high.
SonOfWade Posted June 23, 2010 Posted June 23, 2010 To get the 296, I took the 8x6x18 and took one off each dimension. After I posted, I realized I should have taken two off each dimension. Figure out how many AREN'T touching (i.e., use each dimension minus two to determine it's volume) then subtract that from 864. BillsFanInTexas, I think you are counting some of the cubes two or three times.
Jim in Anchorage Posted June 23, 2010 Posted June 23, 2010 6 layers of 144. All 144 bottom pieces touching. top 5 layers touching on ends and sides. 16 end pieces a layer @ 5 layers=80. 32 side pieces a layer@ 5 layers=160.[this excludes already counted end pieces] 384. Unless you consider all top pieces touching. 480.
Pete Posted June 23, 2010 Posted June 23, 2010 are the sugar cubes wrapped? Then zero would be touching the box
linksfiend Posted June 23, 2010 Posted June 23, 2010 8 wide x 6 high x 18 long Top & bottom = 18x8 = 144x2 = 288 Long sides = 18x(6-2) = 72x2 = 144 (-2 for top and bottom edges already counted) Ends = (8-2)x(6-2) = 24x2 = 48 (-2 both times for all 4 edges already counted) sum = 480
DC Tom Posted June 23, 2010 Posted June 23, 2010 To get the 296, I took the 8x6x18 and took one off each dimension. After I posted, I realized I should have taken two off each dimension. Figure out how many AREN'T touching (i.e., use each dimension minus two to determine it's volume) then subtract that from 864. BillsFanInTexas, I think you are counting some of the cubes two or three times. Figured it the same way. Cubes touching = (total cubes) - (cubes not touching), where (cubes not touching) is bounded by a box 2" smaller in each dimension (1" for each exterior rectangle of cubes). Easiest way to do it.
Jim in Anchorage Posted June 23, 2010 Posted June 23, 2010 8 wide x 6 high x 18 long Top & bottom = 18x8 = 144x2 = 288 Long sides = 18x(6-2) = 72x2 = 144 (-2 for top and bottom edges already counted) Ends = (8-2)x(6-2) = 24x2 = 48 (-2 both times for all 4 edges already counted) sum = 480 I think I already said that
Chandler#81 Posted June 23, 2010 Posted June 23, 2010 Cubes are so last week - buy blotter. Stuck, y'aint right..
Dan Posted June 23, 2010 Posted June 23, 2010 Isn't this kinda like how many golf balls are in the air at any given time in Canada? So, I'm going to say all of them, because math hurts.
stuckincincy Posted June 23, 2010 Posted June 23, 2010 Stuck, y'aint right.. Likely so - my info is at least 30 years old. I used so last week because I know that youngsters use the expression - several years ago. I suppose. That's the best I can do! BTW - your Best Street bus incident - 1967? 1968? I remember the so-called "Shotgun Line" along Bailey (I think) down by William that stopped the rioters that were burning up and looting the Fruit Belt.
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